document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1127297>Question 1127297</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Using 45- in fabric, regan needs  4 3/4 yd for a dress, 6/7 yd of contrasting fabric for the band st the bottom, and 1 1/4 yd for a coordinating jacket. How many yards of a 45- in fabric are needed in all?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #743682 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=743682\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 4 3/4+1 1/4+6/7<BR>\n" );
document.write( "The first two add to 6<BR>\n" );
document.write( "the total is 6 6/7 yards.\r<BR>\n" );
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document.write( "Look for fractions that add to an integer before converting everything to the least common denominator.\r<BR>\n" );
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