document.write( "Question 1127249: If a committee of 6 is being selected from a group of 10 men and 12 women, in how many ways can this committee be arranged if at least 3 must be women? \n" ); document.write( "
Algebra.Com's Answer #743656 by math_helper(2461)\"\" \"About 
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\n" ); document.write( "C(10,3)*C(12,3) = number of committees with 3 men and 3 women
\n" ); document.write( "+C(10,2)*C(12,4) = number of committees with 2 men and 4 women
\n" ); document.write( "+C(10,1)*C(12,5) = number of committees with 1 man and 5 women
\n" ); document.write( "+C(10,0)*C(12,6) = number of committees with no men and 6 women
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\n" ); document.write( "= (120)*(220) + (45)*(495) + (10)*(792) + (1)*(924)
\n" ); document.write( "= 26400 + 22275 + 7920 + 924
\n" ); document.write( "= \"+highlight%28+57519+%29+\" ways
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\n" ); document.write( "\n" ); document.write( "(assuming I haven't made an error in the calculations)
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