document.write( "Question 1127249: If a committee of 6 is being selected from a group of 10 men and 12 women, in how many ways can this committee be arranged if at least 3 must be women? \n" ); document.write( "
Algebra.Com's Answer #743656 by math_helper(2461)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "C(10,3)*C(12,3) = number of committees with 3 men and 3 women \n" ); document.write( "+C(10,2)*C(12,4) = number of committees with 2 men and 4 women \n" ); document.write( "+C(10,1)*C(12,5) = number of committees with 1 man and 5 women \n" ); document.write( "+C(10,0)*C(12,6) = number of committees with no men and 6 women \n" ); document.write( " \n" ); document.write( "= (120)*(220) + (45)*(495) + (10)*(792) + (1)*(924) \n" ); document.write( "= 26400 + 22275 + 7920 + 924 \n" ); document.write( "= \r \n" ); document.write( "\n" ); document.write( "(assuming I haven't made an error in the calculations) \n" ); document.write( "---- \n" ); document.write( " \n" ); document.write( " |