document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=102193>Question 102193</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Each side of equilateral triangle ABC has a length of 8. AR is the altitude to BC. If point E is the midpoint of AR, find the length of BE. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74363 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74363\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let AR=a<BR>\n" );
document.write( "a^2+4^2=8^2 pythagoras a^2+(BR)^2=(AB)^2<BR>\n" );
document.write( "a^2+16=64<BR>\n" );
document.write( "a^2=48<BR>\n" );
document.write( "a=sqrt(16*3)=4*sqrt(3)<BR>\n" );
document.write( "so ER=4sqrt(3)/2=2sqrt(3)<BR>\n" );
document.write( "Let c=BE<BR>\n" );
document.write( "4^2+(2sqrt(3))^2=c^2 pythagorus (BR)^2+(ER)^2=c^2<BR>\n" );
document.write( "16+12=c^2<BR>\n" );
document.write( "c^2=28<BR>\n" );
document.write( "c=sqrt(7*4)=2sqrt(7)<BR>\n" );
document.write( "Ed<BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );