document.write( "Question 1127232: A rectangle has a fixed perimeter of 350 but the length and width of the rectangle can vary. Define a function g that determines the area of the rectangle (in square inches) given the length of the rectangle in inches, l. \n" ); document.write( "
Algebra.Com's Answer #743598 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! A rectangle has a fixed perimeter of 350 but the length and width of the rectangle can vary. Define a function g that determines the area of the rectangle (in square inches) given the length of the rectangle in inches, l. \n" ); document.write( "----- \n" ); document.write( "If perimeter is 350 length + width = 350/2 = 175 \n" ); document.write( "Width = 175-Length \n" ); document.write( "----- \n" ); document.write( "Area = length*width = L(175-L) \n" ); document.write( "---- \n" ); document.write( "Ans:: A(L) = 175L-L^2 \n" ); document.write( "------- \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "------- \n" ); document.write( " |