document.write( "Question 1127209: The remainder of x^3+ax+b when divided by (x^2-1) is x+2. Find a and b. \n" ); document.write( "
Algebra.Com's Answer #743570 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( " if \"x%5E3%2Bax%2Bb\" when \"divided\" by \"%28x%5E2-1%29\" is \"x%2B2\", then\r
\n" ); document.write( "\n" ); document.write( "when \"%28x%5E2-1%29\" \"multiplied+by++%7B%7B%7Bx%2B2\" is \"x%5E3%2Bax%2Bb\"\r
\n" ); document.write( "\n" ); document.write( "so, multiply \"%28x%5E2-1%29%28x%2B2%29\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E3-x-x-2\"\r
\n" ); document.write( "\n" ); document.write( "\"x%5E3-2x-2\" now compare to \"x%5E3%2Bax%2Bb\" and you see that \"a=-2\" and \"b=-2\"
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