document.write( "Question 1127178: Solve for the logistic function with initial condition = 14, limit to growth = 42 and passing through (1, 28)\r
\n" ); document.write( "\n" ); document.write( "Thank you!
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Algebra.Com's Answer #743541 by greenestamps(13203)\"\" \"About 
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\n" ); document.write( "The standard form of a logistic function is

\n" ); document.write( "\"f%28x%29+=+c%2F%281%2Bab%5Ex%29\"

\n" ); document.write( "The \"ab^x\" in the denominator is a decreasing exponential function; as x gets very large that exponential goes to zero, so the denominator goes to 1. That means the numerator c is the limiting value of the function.

\n" ); document.write( "So in this example we know the function is of the form

\n" ); document.write( "\"f%28x%29+=+42%2F%281%2Bab%5Ex%29\"

\n" ); document.write( "The initial value of the function is when x is 0. When x is 0, the denominator of the function is just 1+a. Use the given initial value to find the value of a.

\n" ); document.write( "\"f%280%29+=+42%2F%281%2Bab%5E0%29+=+42%2F%281%2Ba%29+=+14\"
\n" ); document.write( "\"1%2Ba+=+3\"
\n" ); document.write( "\"a+=+2\"

\n" ); document.write( "Now we know the function is of the form

\n" ); document.write( "\"f%28x%29+=+42%2F%281%2B2b%5Ex%29\"

\n" ); document.write( "Now, to finish finding the logistic function, find the value of b by using the given data point.

\n" ); document.write( "\"f%281%29+=+42%2F%281%2B2b%5E1%29+=+28\"
\n" ); document.write( "\"42%2F%281%2B2b%29+=+28\"
\n" ); document.write( "\"42+=+28%2B56b\"
\n" ); document.write( "\"14+=+56b\"
\n" ); document.write( "\"b+=+1%2F4\"

\n" ); document.write( "The logistic function for this problem is

\n" ); document.write( "\"f%28x%29+=+42%2F%281%2B2%281%2F4%29%5Ex%29\"

\n" ); document.write( "A graph, including horizontal lines at the initial, intermediate, and limiting values of 14, 28, and 42:

\n" ); document.write( "\"graph%28400%2C400%2C-1%2C5%2C-10%2C50%2C42%2F%281%2B2%28.25%5Ex%29%29%2C14%2C28%2C42%29\"
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