document.write( "Question 1127187: The unemployment rate in a certain country was 5.1% in January 2004 and 7.5% in January 2005.
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document.write( "Use this model to predict the unemployment rate in January 2006.\r
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document.write( "*I found the model that represents the linear function: 2.4t + 5.1. And so I assumed that by subtracting 2006-2004 and plug in 2 for x would give me the estimated rate. 2.4(2) + 5.1=1.06. Can someone explain where I am going wrong? \n" );
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Algebra.Com's Answer #743530 by Theo(13342)![]() ![]() You can put this solution on YOUR website! the unemployment rate was 5.1% in janury of 2004 and 7.5% in january of 2005. \n" ); document.write( "if you subtract 2004 from 2005, you will get 7.5% - 5.1% = 2.4%. \n" ); document.write( "the equation is correct at 2.4 * T + 5.1 \n" ); document.write( "the number of years from 2004 to 2006 is 2. \n" ); document.write( "you are correct by replacing T with 2. \n" ); document.write( "the equation becomes 2.4 * 2 + 5.1 which is equal to 4.8 + 5.1 which is equal to 9.9. \n" ); document.write( "i have no idea how you got 1.06. \n" ); document.write( "i tried different things and the closest i got to 1.06 is that you divided 5.1 by 4.8 and got 1.0625. \n" ); document.write( "if that's what you did, then you must have gotten confused as to what you were doing. \n" ); document.write( "all you had to do was make T = 2 and apply it to to formula as shown. \n" ); document.write( "2.4T + 5.1 is the same as 2.4 * T + 5.1 which results in 2.4 * 2 + 5.1 which results in 4.8 + 5.1 which results in 9.9. \n" ); document.write( "the equation of y = 2.4 * T + 5.1 can be graphed by replacing T with x as shown below. \n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |