document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1127101>Question 1127101</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given a binomial experiment where the probability of success on a single trial is 25% and the experiment is repeated 4 times, and where the number of successes is counted, perform the following calculations:\r<BR>\n" );
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document.write( "-Make a complete probability distribution table of this experiment. List every possible value of X and the corresponding probability.<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #743453 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=743453\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Pascal's triangle for 4 runs<BR>\n" );
document.write( "1 has 0 successes 4 failures.  That would be 0.3164 or 0.75^4<BR>\n" );
document.write( "4 has 1 success 3 failures  That would be 0.25*0.75^3*4 or 0.4219<BR>\n" );
document.write( "6 has 2 successes 2 failures  That would be 0.25^2*0.75^2*6 or 0.2109<BR>\n" );
document.write( "4 has 3 successes 1 failure  That would be 0.25^3*0.75*4 or 0.0469<BR>\n" );
document.write( "1 has 4 successes 0 failures. That would be 0.25^4 or 0.0039<BR>\n" );
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