document.write( "Question 1127085: show that the general term of the sequence -2/5,1/0,4/15,7/20,0/25,...can be written as Tn =3n -5/5n \n" ); document.write( "
Algebra.Com's Answer #743444 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Given the form for Tn, it is clear that you have a typo in the given sequence. The second term is 1/10, not 1/0; the 5th term is 10/25, not 0/25. \n" ); document.write( "It would be polite (and beneficial to you) for you to look at what you have written in your post before submitting it. \n" ); document.write( "Then there is not much to show.... \n" ); document.write( "The numerators are -2, 1, 4, 7, 10,...; they follow the pattern 3n-5. The denominators are 5, 10, 15, 20, 25,...; they follow the pattern 5n. \n" ); document.write( "So the fractions follow the pattern (3n-5)/(5n). \n" ); document.write( " |