document.write( "Question 1127031: Gravel is being dumped from a conveyor belt at a rate of 15 ft3/min, and its coarseness is such that it forms a pile in the shape of a cone whose base diameter and height are always equal. How fast is the height of the pile increasing when the pile is 5 ft high? (Round your answer to two decimal places.) \n" ); document.write( "
Algebra.Com's Answer #743409 by ikleyn(52781)\"\" \"About 
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document.write( "The volume of a cone   V = \"%281%2F3%29%2Api%2Ar%5E2%2Ah\".\r\n" );
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document.write( "Since we are given that  h = 2r (where 2r is the diameter), \r\n" );
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document.write( "    V = \"%281%2F3%29%2Api%2A%28h%2F2%29%5E2%2Ah\" = \"%281%2F3%29%2Api%2A%281%2F4%29%2Ah%5E3\" = \"%28pi%2F12%29%2Ah%5E3\".    (1)\r\n" );
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document.write( "The rate of the volume change in time is given;  it is 15 \"%28ft%29%5E3%2F%28min%29\";  therefore\r\n" );
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document.write( "15 = \"%28dV%29%2F%28dt%29\" = \"%28%28dV%29%2F%28dh%29%29%2A%28%28dh%29%2F%28dt%29%29\" = (calculate \"%28dV%29%2F%28dh%29\" from the formula (1)) = \"%28pi%2F4%29%2Ah%5E2\".\"%28dh%29%2F%28dt%29\" = (substitute here h= 5 ft) = \"%28pi%2F4%29%2A25\".\"%28dh%29%2F%28dt%29\".\r\n" );
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document.write( "It implies  \"%28dh%29%2F%28dt%29\" = \"15%2F%28%28pi%2F4%29%2A25%29\" = \"%283%2A4%29%2F%285%2Api%29\" = \"12%2F%285%2Api%29\" = 0.76 ft/min.  (rounded)\r\n" );
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document.write( "Answer.  At this moment, the height of the cone is increasing at the rate of  0.76 ft/min. (approximately)\r\n" );
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