document.write( "Question 1127025: A nursery sells KB seed for $5.75/lbs and TF seed for $4.50/lbs. The nursery sells a mixture of the two kinds of seed for $5.25/lbs. Let K represent the amount of KB seed the nursery uses in 5 pounds of the mixture. \n" ); document.write( "
Algebra.Com's Answer #743401 by greenestamps(13200)\"\" \"About 
You can put this solution on YOUR website!


\n" ); document.write( "Oh, brother!!!!

\n" ); document.write( "It is NOT \"against the rules of this forum\" to respond to a message if it is clear what the question is.

\n" ); document.write( "The other tutor's response is appropriate, and correct.

\n" ); document.write( "Here is a way that will get you to the answer to a question like this much faster and with much less work than the standard algebraic method used by the other tutor.

\n" ); document.write( "(1) The $5.25 cost per pound is 3/5 of the way from the $4.50 per pound cost of the TF seed to the $5.75 per pound cost of the KB seed.

\n" ); document.write( "(Do some simple arithmetic: 5.25 - 4.50 = .75; 5.75-4.50 = 1.25; .75/1.25 = 3/5)

\n" ); document.write( "(2) That means 3/5 of the mixture needs to be the higher priced KB seed.

\n" ); document.write( "Therefore, to make 5 pounds of the mixture, you need 3 pounds of the KB seed and 2 pounds of the TF seed.
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