document.write( "Question 1127041: Trina's boat travels 20 km/h in still water. A river has a current that flows at a rate of 5 km/h. Trina travels in her boat downstream for 1 km and then returns to her starting point. Her average rate, in km, is....?\r
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Algebra.Com's Answer #743373 by ikleyn(52790)\"\" \"About 
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document.write( "Her speed downstream is 20 + 5 = 25 km/h.\r\n" );
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document.write( "She spent  \"1%2F25\" of an hour traveling 1 kilometer downstream.\r\n" );
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document.write( "Her speed upstream is 20 - 5 = 15 km/h.\r\n" );
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document.write( "She spent  \"1%2F15\" of an hour traveling 1 kilometer for the returning trip upstream.\r\n" );
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document.write( "In all, she spent  \"1%2F25\" + \"1%2F15\" hours = \"3%2F75+%2B+5%2F75\" = \"8%2F75\" hours.\r\n" );
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document.write( "The average rate is the total distance, which is 1 + 1 = 2 kilometers, divided by the total time, which is  \"8%2F25\" hours:\r\n" );
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document.write( "    the average rate = \"2%2F%28%288%2F75%29%29\" = \"%282%2A75%29%2F8\" = \"75%2F4\" = 18.75 kilometers per hour.    ANSWER\r\n" );
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