document.write( "Question 1126980: If x+y =3, then find x³+y³+10xy
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Algebra.Com's Answer #743350 by ikleyn(52858)\"\" \"About 
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document.write( "\"x%5E3+%2B+y%5E3+%2B+10xy\" = \"x%5E3+%2B+y%5E3+%2B+3%2Axy%2A3+%2B+xy\" = \r\n" );
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document.write( "    in 3*xy*3 replace the second factor 3 by (x+y), based on what is given. Then you can continue this chain of equalities as \r\n" );
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document.write( "= \"x%5E3+%2B+y%5E3+%2B+3xy%28x%2By%29\" + \"xy\" = \"x%5E3+%2B+3x%5E2y+%2B+3xy%5E2+%2B+y%5E3\" + xy = \"%28x%2By%29%5E3\" + xy = \r\n" );
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document.write( "    Replace (x+y) by 3 again, based on what is given. Then you can continue\r\n" );
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document.write( "= \"3%5E3\" + xy = 27 + xy.\r\n" );
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document.write( "That is all that can be done.\r\n" );
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