document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1126986>Question 1126986</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of the circle concentric with the circle <BR>\n" );
document.write( "x*2+y*2- 6x+ 2y- 11 = 0 and passing through the centre of the circle <BR>\n" );
document.write( "x*2+y*2= 16. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #743314 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=743314\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> rewrite the first as <BR>\n" );
document.write( "x^2-6x+y^2+2y=11<BR>\n" );
document.write( "complete the square<BR>\n" );
document.write( "x^2-6x+9+y^2+2y+1=21<BR>\n" );
document.write( "(x-3)^2+(y+1)^2=21<BR>\n" );
document.write( "first circle has center at (3, -1) and radius sqrt (21)<BR>\n" );
document.write( "The circle concentric with this has center (3, -1) and passes through the origin, since the center of x^2+y^2=16 is a circle with center (0, 0) and radius 4\r<BR>\n" );
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document.write( "The radius of the second circle is the distance from the center to the origin, which is sqrt (10).<BR>\n" );
document.write( "Its equation is (x-3)^2+(y+1)^2=10  ANSWER<BR>\n" );
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