document.write( "Question 102274: Solve the system by the addition method:\r
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document.write( "Eq 1 states: 3x = 3 + 2y
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document.write( "Eq 2 states: -4/3x + y = 1/3 \n" );
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Algebra.Com's Answer #74327 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! Solve the system by the addition method:\r \n" ); document.write( "\n" ); document.write( "Eq 1 states: 3x = 3 + 2y \n" ); document.write( "Eq 2 states: (-4/3)x + y = 1/3 \n" ); document.write( "------------------ \n" ); document.write( "Rearrange Eq 1 and multiply thru Eq 2 by 3 to get: \n" ); document.write( "#3: 3x-2y=3 \n" ); document.write( "#4: -4x+3y=1 \n" ); document.write( "-------------- \n" ); document.write( "Multiply #3 by 3 and #4 by 2 to get: \n" ); document.write( "#5: 9x-6y=9 \n" ); document.write( "#6:-8x+6y=2 \n" ); document.write( "------------- \n" ); document.write( "Add to get: \n" ); document.write( "x = 11 \n" ); document.write( "--------- \n" ); document.write( "Substitute into #3 to solve for y: \n" ); document.write( "3*11-2y=3 \n" ); document.write( "2y = 30 \n" ); document.write( "y = 15 \n" ); document.write( "------------ \n" ); document.write( "Check the answer in -4x+3y=1 \n" ); document.write( "-4*11 + 3*15 = 1 \n" ); document.write( "-44+45 = 1 \n" ); document.write( "1=1 \n" ); document.write( "============ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( " |