document.write( "Question 1126936: There consecutive odd numbers are such that the square of the first is 72 less than the square of the third. Find the three numbers. \n" ); document.write( "

Algebra.Com's Answer #743266 by josmiceli(19441) $\"\"$ $\"About$

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Let the consecutive odd numbers be
\n" ); document.write( "n, n+2, and n+4
\n" ); document.write( "-----------------------
\n" ); document.write( " $\"+n%5E2+=+%28+n+%2B+4+%29%5E2+-+72+\"$
\n" ); document.write( " $\"+n%5E2+=+n%5E2+%2B+8n+%2B+16+-+72+\"$
\n" ); document.write( " $\"+0+=+8n+-+56+\"$
\n" ); document.write( " $\"+8n+=+56+\"$
\n" ); document.write( " $\"+n+=+7+\"$
\n" ); document.write( " $\"+n+%2B+2+=+9+\"$
\n" ); document.write( " $\"+n+%2B+4+=+11+\"$
\n" ); document.write( "7, 9, and 11
\n" ); document.write( "----------------
\n" ); document.write( "check:
\n" ); document.write( " $\"+7%5E2+=+11%5E2+-+72+\"$
\n" ); document.write( " $\"+49+=+121+-+72+\"$
\n" ); document.write( " $\"+49+=+49+\"$
\n" ); document.write( "OK \n" ); document.write( "

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