document.write( "Question 1126924: Solve the following problem from Pacioli – A mouse is at the top of a poplar tree that is 60 feet high, and a cat is on the ground at its foot. The mouse descends 1⁄2 of a foot each day, and at night it turns back 1/6 of a foot. The cat climbs 1 foot a day and slips back 1⁄4 of a foot each night. The tree grows 1⁄4 of a foot between the cat and the mouse each day and shrinks 1/8 of a foot each night. How long will it take the cat to reach the mouse? \n" ); document.write( "
Algebra.Com's Answer #743259 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Let \"+t+\" = number of [1 day + 1 night] intervals
\n" ); document.write( "The mouse's rate of descent is \"+%281%2F3%29%2F1+\"
\n" ); document.write( "The cat's rate of ascent is \"+%283%2F4%29%2F1+\"
\n" ); document.write( "I can add their rates since they are going toward each other
\n" ); document.write( "Subtract the rate of growth of the tree \"+%281%2F8%29%2F1+\"
\n" ); document.write( "------------------------
\n" ); document.write( "\"+%281%2F3%29%2At+%2B+%283%2F4%29%2At+-+%281%2F8%29%2At+=+60+\"
\n" ); document.write( "Multiply both sides by \"+48+\"
\n" ); document.write( "\"+16t+%2B+36t+-+6t+=+2880+\"
\n" ); document.write( "\"+46t+=+2880+\"
\n" ); document.write( "\"+t+=+62.6087+\"
\n" ); document.write( "I would say it takes 31 days and 32 nights
\n" ); document.write( "get another opinion definitely\r
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