document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1126914>Question 1126914</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Prove the following identity.\r<BR>\n" );
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document.write( "cos2x/sinx = cscx-2sinx\r<BR>\n" );
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document.write( "How do I go about this problem? I'm stuck on where to start and any help would be greatly appreciated.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #743233 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=743233\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use cos^2 x- sin^2 x for cos2x\r<BR>\n" );
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document.write( "and cos^2 x=(1-sin^2 x)<BR>\n" );
document.write( "so the left side becomes (1/sin x) (1-2 sin^2 x)<BR>\n" );
document.write( "this is (1/sin x)(-2 sin x), dividing both terms by sin x.<BR>\n" );
document.write( "or csc x-2 sin x </SPAN>\n" );
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