document.write( "Question 1126913: John leaves home at 9 am and walks 4 mph. His brother Greg, leaves half an hour later and runs 8.5 mph in the same direction. Predict the time at which Greg will catch up to John. How do you solve this? \n" ); document.write( "

Algebra.Com's Answer #743230 by josgarithmetic(39621) $\"\"$ $\"About$

You can put this solution on YOUR website!
How MUCH time Greg traveled, x\r
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\n" ); document.write( "\n" ); document.write( " $\"4%28x%2B0.5%29=8.5%2Ax\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"x=%284%2F9%29%2Ahours\"$ \r
\n" ); document.write( "\n" ); document.write( "About 9:27 AM, when Greg catches up\r
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\n" ); document.write( "\n" ); document.write( "Upon catchup , each traveled the same distance,
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document.write( "          SPEED      TIME QUANTITY      DISTANCE\r\n" );
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document.write( "JOHN       4         x+0.5               4(x+0.5)\r\n" );
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document.write( "GREG       8.5         x                 8.5x\r\n" );
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document.write( "Equate the two distance expressions.\r\n" );
document.write( "Solve for x.\r\n" );
document.write( "Apply x to the given time.\r\n" );
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