document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=102154>Question 102154</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A tennis ball can in the shape of a cylinder with a flat top and bottom of the same radius as the tennis balls is designed so the space inside the can that is not occupied by the balls has a volume at most equal to the volume of one ball. What is the largest number of balls that the can will contain? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74319 by </B><A HREF=/tutors/aboutme.mpl?userid=edjones><B>edjones(8007)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=edjones><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=edjones><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74319\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Cylinder A=pi*r^2*h<BR>\n" );
document.write( "Sphere A= 4/3*pi*r^3<BR>\n" );
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document.write( "for 1 ball with a radius of 1<BR>\n" );
document.write( "Cylinder A=6/3*pi (h=2r=6/3)<BR>\n" );
document.write( "Sphere A= 4/3*pi<BR>\n" );
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document.write( "difference 2/3*pi<BR>\n" );
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document.write( "for 2 ball with a radius of 1<BR>\n" );
document.write( "Cylinder A=12/3*pi<BR>\n" );
document.write( "Sphere A= 8/3*pi<BR>\n" );
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document.write( "difference 4/3*pi= volume of 1 ball<BR>\n" );
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document.write( "Can will hold no more than 2 balls.<BR>\n" );
document.write( "Ed<BR>\n" );
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