document.write( "Question 102260: Find the equation of the line passing through the points (-1, 4) and (5, 2). \n" ); document.write( "
Algebra.Com's Answer #74316 by jim_thompson5910(35256)\"\" \"About 
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First lets find the slope through the points (\"-1\",\"4\") and (\"5\",\"2\")\r
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\n" ); document.write( "\n" ); document.write( "\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\" Start with the slope formula (note: is the first point (\"-1\",\"4\") and is the second point (\"5\",\"2\"))\r
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\n" ); document.write( "\n" ); document.write( "\"m=%282-4%29%2F%285--1%29\" Plug in \"y%5B2%5D=2\",\"y%5B1%5D=4\",\"x%5B2%5D=5\",\"x%5B1%5D=-1\" (these are the coordinates of given points)\r
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\n" ); document.write( "\n" ); document.write( "\"m=+-2%2F6\" Subtract the terms in the numerator \"2-4\" to get \"-2\". Subtract the terms in the denominator \"5--1\" to get \"6\"\r
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\n" ); document.write( "\n" ); document.write( "\"m=-1%2F3\" Reduce\r
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\n" ); document.write( "\n" ); document.write( "So the slope is\r
\n" ); document.write( "\n" ); document.write( "\"m=-1%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Now let's use the point-slope formula to find the equation of the line:\r
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\n" ); document.write( "\n" ); document.write( "------Point-Slope Formula------
\n" ); document.write( "\"y-y%5B1%5D=m%28x-x%5B1%5D%29\" where \"m\" is the slope, and is one of the given points\r
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\n" ); document.write( "\n" ); document.write( "So lets use the Point-Slope Formula to find the equation of the line\r
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\n" ); document.write( "\n" ); document.write( "\"y-4=%28-1%2F3%29%28x--1%29\" Plug in \"m=-1%2F3\", \"x%5B1%5D=-1\", and \"y%5B1%5D=4\" (these values are given)\r
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\n" ); document.write( "\n" ); document.write( "\"y-4=%28-1%2F3%29%28x%2B1%29\" Rewrite \"x--1\" as \"x%2B1\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-4=%28-1%2F3%29x%2B%28-1%2F3%29%281%29\" Distribute \"-1%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y-4=%28-1%2F3%29x-1%2F3\" Multiply \"-1%2F3\" and \"1\" to get \"-1%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-1%2F3%29x-1%2F3%2B4\" Add \"4\" to both sides to isolate y\r
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\n" ); document.write( "\n" ); document.write( "\"y=%28-1%2F3%29x%2B11%2F3\" Combine like terms \"-1%2F3\" and \"4\" to get \"11%2F3\" (note: if you need help with combining fractions, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "Answer:\r
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\n" ); document.write( "\n" ); document.write( "So the equation of the line which goes through the points (\"-1\",\"4\") and (\"5\",\"2\") is:\"y=%28-1%2F3%29x%2B11%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "The equation is now in \"y=mx%2Bb\" form (which is slope-intercept form) where the slope is \"m=-1%2F3\" and the y-intercept is \"b=11%2F3\"\r
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\n" ); document.write( "\n" ); document.write( "Notice if we graph the equation \"y=%28-1%2F3%29x%2B11%2F3\" and plot the points (\"-1\",\"4\") and (\"5\",\"2\"), we get this: (note: if you need help with graphing, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( " Graph of \"y=%28-1%2F3%29x%2B11%2F3\" through the points (\"-1\",\"4\") and (\"5\",\"2\")\r
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\n" ); document.write( "\n" ); document.write( "Notice how the two points lie on the line. This graphically verifies our answer.
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