document.write( "Question 102205: The length of a rectangle is 2 in. more than twice its width. If the
\n" ); document.write( "perimeter of the rectangle is 34 in., find the dimensions of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #74309 by doukungfoo(195)\"\" \"About 
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Ok first we have to know the formula for perimeter of a rectangle.
\n" ); document.write( "Perimeter = 2(Length) + 2(Width)
\n" ); document.write( "So for this rectangle lets call the width x
\n" ); document.write( "Width = x
\n" ); document.write( "Now we are told that the length is 2 in more than twice its width.
\n" ); document.write( "So if the width is x then
\n" ); document.write( "Length = 2x + 2
\n" ); document.write( "We are also told that the perimeter is 34 in
\n" ); document.write( "Ok so lets put all this into the perimeter formula and solve for x
\n" ); document.write( "Perimeter = 2(Length) + 2(Width)
\n" ); document.write( "34 = 2(2x+2) + 2(x)
\n" ); document.write( "34 = 4x + 4 + 2x
\n" ); document.write( "34 = 6x + 4
\n" ); document.write( "30 = 6x
\n" ); document.write( "5 = x
\n" ); document.write( "Answer: The width is 5 inches
\n" ); document.write( "Now use this to find the length
\n" ); document.write( "Length = 2x + 2
\n" ); document.write( "Length = 2(5) + 2
\n" ); document.write( "Length = 10 + 2
\n" ); document.write( "Length = 12
\n" ); document.write( "Answer: The length is 12 inches
\n" ); document.write( "Check answers using the perimeter formula
\n" ); document.write( "Perimeter = 2(Length) + 2(Width)
\n" ); document.write( "34 = 2(12) + 2(5)
\n" ); document.write( "34 = 24 + 10
\n" ); document.write( "34 = 34\r
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