document.write( "Question 1126760: The graph of a line passes through the points (0, -2) and (6, 0). What is the equation of the line?
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Algebra.Com's Answer #743088 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "the equation of the line:\r
\n" ); document.write( "\n" ); document.write( "\"y=mx%2Bb\" where \"m\" is a slope and \"b\" is y-intercept\r
\n" ); document.write( "\n" ); document.write( "use given points to ind a slope: (\"0\", \"-2\") and (\"6\", \"0\")\r
\n" ); document.write( "\n" ); document.write( "\"m=%28y%5B2%5D-y%5B1%5D%29%2F%28x%5B2%5D-x%5B1%5D%29\"\r
\n" ); document.write( "\n" ); document.write( "\"m=%280-%28-2%29%29%2F%286-0%29\"\r
\n" ); document.write( "\n" ); document.write( "\"m=2%2F6\"\r
\n" ); document.write( "\n" ); document.write( "\"m=1%2F3\"\r
\n" ); document.write( "\n" ); document.write( "since \"b\" is y-intercept, and we know that y-intercept is at (\"0\", \"y\"), from given point (\"0\", \"-2\") we see that \"b=-2\"\r
\n" ); document.write( "\n" ); document.write( "so, your equation is\r
\n" ); document.write( "\n" ); document.write( "\"y=%281%2F3%29x-2\" \r
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