document.write( "Question 1126750: What is the value of cos(2α) , if sin(3α) =2 sin(α)? \n" ); document.write( "
Algebra.Com's Answer #743079 by MathLover1(20850)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( " What is the value of \"cos%282alpha%29\" , if \r
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\n" ); document.write( "\n" ); document.write( "\"sin%283alpha%29+=2+sin%28alpha%29\"? \r
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\n" ); document.write( "\n" ); document.write( "use the following identity: \r
\n" ); document.write( "\n" ); document.write( "\"sin%283alpha%29+=+3+sin%28alpha%29+cos%5E2%28alpha%29+-+sin%5E3%28alpha%29\"\r
\n" ); document.write( "\n" ); document.write( "factor it: \r
\n" ); document.write( "\n" ); document.write( "\"sin%283alpha%29+=sin%28alpha%29%28+3+cos%5E2%28alpha%29+-+sin%5E2%28alpha%29%29\"\r
\n" ); document.write( "\n" ); document.write( "use identity \"sin%5E2%28alpha%29=1-cos%5E2%28alpha%29\" \r
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\n" ); document.write( "\n" ); document.write( "\"sin%283alpha%29+=sin%28alpha%29%28+3+cos%5E2%28alpha%29+-+%281-cos%5E2%28alpha%29%29+%29\"\r
\n" ); document.write( "\n" ); document.write( "\"sin%283alpha%29+=sin%28alpha%29%28+3+cos%5E2%28alpha%29+-+1%2Bcos%5E2%28alpha%29%29+%29\"\r
\n" ); document.write( "\n" ); document.write( "\"sin%283alpha%29+=sin%28alpha%29%28+4cos%5E2%28alpha%29+-+1+%29\"\r
\n" ); document.write( "\n" ); document.write( "then we have\r
\n" ); document.write( "\n" ); document.write( "\"sin%28alpha%29%28+4cos%5E2%28alpha%29+-+1+%29=2sin%28alpha%29\"\r
\n" ); document.write( "\n" ); document.write( "\"cross%28sin%28alpha%29%29%28+4cos%5E2%28alpha%29+-+1+%29=2cross%28sin%28alpha%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"4cos%5E2%28alpha%29+-+1+%29=2\"...simplify, divide by\"+2\"\r
\n" ); document.write( "\n" ); document.write( "\"2cos%282+alpha%29+-+1=1\"\r
\n" ); document.write( "\n" ); document.write( "\"2cos%282alpha%29+=2\"\r
\n" ); document.write( "\n" ); document.write( "\"+cos%282alpha%29+=1\"\r
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