document.write( "Question 1126697: A company that sells yogurts has found that their machine that fills the 8oz containers of yogurt is not perfect. In reality, the mean weight is 7.98 oz and the standard deviation in the weights is 0.05 oz. The weights are normally distributed.
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document.write( "Use the 68-95-99.7 rule and symmetry to answer the question.\r
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document.write( "my question is how do I compute this problem\r
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document.write( "What percent of the yogurts weigh more than 7.98 oz?
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Algebra.Com's Answer #743026 by FrankM(1040)![]() ![]() You can put this solution on YOUR website! 50%\r \n" ); document.write( "\n" ); document.write( "Mean (average) is the same as Median (middle number) for normal distribution. \r \n" ); document.write( "\n" ); document.write( "50% of the data will be higher than the mean/median. \n" ); document.write( " |