document.write( "Question 1126666: A rectangle has length 15 cm and width y cm. If its perimeter is more than 50 cm but less than 70 cm, find the range of values of y.
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document.write( "A. 10 < y < 14
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document.write( "B. 10 < y < 20
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document.write( "C. 20 < y < 30
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document.write( "D. 35 < y < 55 \n" );
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Algebra.Com's Answer #742984 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "P = perimeter of rectangle \n" ); document.write( "L = length = 15 \n" ); document.write( "W = width = y \n" ); document.write( "P = 2*(L+W) \n" ); document.write( "P = 2*(15+y) \n" ); document.write( "P = 30+2y\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Since the \"perimeter is more than 50\" we know that P > 50 or 50 < P. \n" ); document.write( "At the same time we're told that the perimeter is \"less than 70\", so P < 70. \n" ); document.write( "Combine 50 < P and P < 70 to get 50 < P < 70\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "50 < P < 70 \n" ); document.write( "50 < 30+2y < 70 Replace P with 30+2y \n" ); document.write( "50-30 < 30+2y-30 < 70-30 subtract 30 from all sides \n" ); document.write( "20 < 2y < 40 \n" ); document.write( "20/2 < 2y/2 < 40/2 divide all sides by 2 \n" ); document.write( "10 < y < 20\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " Answer: Choice B. 10 < y < 20 \n" ); document.write( "This means that y can be anything between 10 and 20 as long as it's not 10, and it's not 20 either. \n" ); document.write( " \n" ); document.write( " |