document.write( "Question 1126608: A bag contains three white balls numbered 2, 4,6, and flour black balls numbered 1,3,5 and 7, two balls are drawn without replacement.
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document.write( "what is the probability the first ball is white given that the second ball is black? \n" );
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Algebra.Com's Answer #742928 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "First ball drawn: There are 7 balls in all; 3 are white. P(white on first draw) = 3/7. \n" ); document.write( "Second ball drawn: Now there are 6 balls in all; 4 are black. P(black on second draw) = 4/6 = 2/3. \n" ); document.write( "P(white on first AND black on second) = P(white on first) * P(black on second) = (3/7)*(2/3) = 2/7. \n" ); document.write( " |