document.write( "Question 1126567: A person owns two shops. This year the telephone bill for the first shop was $530 less than three times the telephone bill for the second shop. The total telephone expense for both shops was $2758. What was the cost of each shop's telephone service for the year? \n" ); document.write( "

Algebra.Com's Answer #742880 by sbro7568(4) $\"\"$ $\"About$

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To represent the bill for the first shop, we will use the variable x. To represent the bill for the second shop, we will use the variable y.\r
\n" ); document.write( "\n" ); document.write( "Since the first shop's bill is $530 less than 3 times the second shop's bill, we can put together an equation for the first shop's bill based on the second shop's: $\"x=3y-530\"$ . \r
\n" ); document.write( "\n" ); document.write( "Now, since the total for both shops was $2758, we can create an equation for the total: $\"x%2By=2758\"$ . \r
\n" ); document.write( "\n" ); document.write( "We can then plug in the first equation we created, $\"x=3y-530\"$ , to replace x, and end up with $\"%283y-530%29%2By=2758\"$ . When we simplify this equation, we get $\"4y-530=2758\"$ . Then, we can add 530 to both sides to get $\"4y=3288%7D%7D%2C+and+then+divide+both+sides+by+4+to+get+%7B%7B%7By=822\"$ . Since y represents the second shop's bill, the bill must be $822 for that shop.\r
\n" ); document.write( "\n" ); document.write( "To get the first shop's bill, we can plug in 822 to the first equation we made, to get $\"x=%283%2A822%29-530\"$ . When we simplify this equation, we get $\"x=1936\"$ . Therefore, the first shop's bill is $1936.\r
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\n" ); document.write( "tl;dr:
\n" ); document.write( "First shop's bill = $1936
\n" ); document.write( "Second shop's bill = $822 \n" ); document.write( "

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