document.write( "Question 1126554: The length of a warehouse is 23 ft more than its width. Find the width and length of the warehouse if its area is 6840 ft^2\r
\n" ); document.write( "\n" ); document.write( "How do you find length and width of a rectangle when given the area?
\n" ); document.write( "

Algebra.Com's Answer #742867 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
area of a rectangle is length * width.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "let L = length and let W = width.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "area of a rectangle becomes L * W.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "if the length is 23 feet more than the width, then L = W + 23.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "replace L with W + 23 in the formula and you get area of a rectangle = (W + 23) * W.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "simplify to get area of the rectangle = 23W + W^2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "since the area is 6840, then the formula becomes 6840 = 23W + W^2\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "subtract 6840 from both sides of the equation and re-order the terms in descending order of degree and flip sides to get:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "W^2 + 23W - 6840 = 0\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "factor this quadratic equation to get:\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "(W+95) * (W-72) = 0\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "solve for W to get W = -95 or W = 72.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "W can't be negative, so W = 72.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "since L = W + 23, then L = 95\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "length is 95 and width is 72\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "area is length * width = 95 * 72 = 6840.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "length is 23 greater than width.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "solution looks good.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "solution is length = 95 and width = 72.\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "even though the quadratic was factor-able, if it wasn't obvious what the factors needed to be, then use the quadratic formula to find the answer.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );