document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1126501>Question 1126501</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Pure acid is to be added to a 10% acid solution to obtain 90 L of 64&#8203;% solution. What amounts of each should be&#8203; used? How many liters of&#8203; 100% pure acid should be used to make the&#8203; solution?  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #742845 by </B><A HREF=/tutors/aboutme.mpl?userid=greenestamps><B>greenestamps(13334)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=greenestamps><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=greenestamps><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=742845\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <br><BR>\n" );
document.write( "Here is a quick and easy alternative to the standard algebraic method for solving mixture problems like this, as shown by the other tutors.<br><BR>\n" );
document.write( "You are adding 100% pure acid to the 10% acid; the percentage of the mixture moves from 10% towards 100%.  You stop when the percentage is 64%.<br><BR>\n" );
document.write( "(1) 64% is 3/5 of the way from 10% to 100%.  (Do a little mental arithmetic: 100-10 = 90; 64-10 = 54; 54/90 = 3/5)<BR>\n" );
document.write( "(2) That means 3/5 of the mixture must be the 100% pure acid you are adding.<br><BR>\n" );
document.write( "3/5 of 90 L is 54 L.  So 54 L of the 100% acid and 36 L of the 10% acid. </SPAN>\n" );
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