document.write( "Question 1126501: Pure acid is to be added to a 10% acid solution to obtain 90 L of 64​% solution. What amounts of each should be​ used? How many liters of​ 100% pure acid should be used to make the​ solution? \n" ); document.write( "
Algebra.Com's Answer #742835 by josgarithmetic(39799)\"\" \"About 
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x of the pure acid
\n" ); document.write( "90-x of the 10% acid\r
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\n" ); document.write( "\n" ); document.write( "\"100x%2B10%2890-x%29=64%2A90\"\r
\n" ); document.write( "\n" ); document.write( "-\r
\n" ); document.write( "\n" ); document.write( "\"10x%2B90-x=64%2A9\"\r
\n" ); document.write( "\n" ); document.write( "\"9x=64%2A9-90\"\r
\n" ); document.write( "\n" ); document.write( "\"x=64-10\"\r
\n" ); document.write( "\n" ); document.write( "\"x=54\"-----liters of the pure, 100% acid.\r
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\n" ); document.write( "\n" ); document.write( "\"cross%2846%29\"\"36\"------liters of the 10% acid.
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