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Algebra.Com's Answer #74282 by jim_thompson5910(35256) $\"\"$ $\"About$

You can put this solution on YOUR website!
Do you want to solve for y?\r
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Solved by pluggable solver: Converting Linear Equations in Standard form to Slope-Intercept Form (and vice versa)

Convert from standard form (Ax+By = C) to slope-intercept form (y = mx+b)

$\"2x%2B2y=8\"$ Start with the given equation

$\"2x%2B2y-2x=8-2x\"$ Subtract 2x from both sides

$\"2y=-2x%2B8\"$ Simplify

$\"%282y%29%2F%282%29=%28-2x%2B8%29%2F%282%29\"$ Divide both sides by 2 to isolate y

$\"y+=+%28-2x%29%2F%282%29%2B%288%29%2F%282%29\"$ Break up the fraction on the right hand side

$\"y+=+-1x%2B4\"$ Reduce and simplify

The original equation $\"2x%2B2y=8\"$ (standard form) is equivalent to $\"y+=+-1x%2B4\"$ (slope-intercept form)

The equation $\"y+=+-1x%2B4\"$ is in the form $\"y=mx%2Bb\"$ where $\"m=-1\"$ is the slope and $\"b=4\"$ is the y intercept.

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