document.write( "Question 1126487: One number is three more than another number. The sum of their squares is 45. Find the numbers \n" ); document.write( "
Algebra.Com's Answer #742816 by josgarithmetic(39617)\"\" \"About 
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\"system%28y-x=3%2Cy%5E2%2Bx%5E2=45%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28y-x%29%5E2=3%5E2\"
\n" ); document.write( "\"y%5E2-2yx%2Bx%5E2=9\"
\n" ); document.write( "\"-2yx%2B45=9\"
\n" ); document.write( "\"-2yx=-36\"
\n" ); document.write( "\"yx=18\"\r
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\n" ); document.write( "\n" ); document.write( "Now find two numbers differ by 3, product of 18.
\n" ); document.write( "2*9, no.
\n" ); document.write( "3*6, yes.\r
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\n" ); document.write( "\n" ); document.write( "Numbers 3 and 6.
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