document.write( "Question 102209: Building on question 95079, I have the part that goes like this:The only part of the height equation that we have not discussed is the constant. You have
\n" ); document.write( "probably noticed that the constant is always equal to the initial height of the ball (80 m in
\n" ); document.write( "our previous exercises). Now, let’s have you develop a height equation.
\n" ); document.write( "A ball is thrown upward from the roof of a building 100 m tall with an initial velocity
\n" ); document.write( "of 20 m/s. Use this information for exercises 35 to 38.
\n" ); document.write( "35. Science and medicine. Write the equation for the height of the ball.
\n" ); document.write( "36. Science and medicine. When will the ball reach a height of 80 m?\r
\n" ); document.write( "\n" ); document.write( "I am trying to solve #36. So far I have:\r
\n" ); document.write( "\n" ); document.write( "h=-5t^2+20t+100
\n" ); document.write( "0=t^2-4-20
\n" ); document.write( "0= 4+or-sqrt-5^2-4*1*-20/2*1
\n" ); document.write( "=4+or-sqrt16+80/2
\n" ); document.write( "4=+or-sqrt96/2
\n" ); document.write( "4+9.8/2=13.8/2=6.9
\n" ); document.write( "4-9.8/2=5.8/2=2.9\r
\n" ); document.write( "\n" ); document.write( "am I anywhere near where I need to be? \r
\n" ); document.write( "\n" ); document.write( "Thank you so much.\r
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Algebra.Com's Answer #74280 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!
\"h=-5t%5E2%2B20t%2B100\" Start with the given equation (assuming you did everything right for problem 35)\r
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\n" ); document.write( "\n" ); document.write( "When the height is 80, this means h=80\r
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\n" ); document.write( "\n" ); document.write( "\"80=-5t%5E2%2B20t%2B100\" So plug in h=80\r
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\n" ); document.write( "\n" ); document.write( "\"0=-5t%5E2%2B20t%2B20\" Subtract 80 from both sides\r
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\n" ); document.write( "\n" ); document.write( "Let's use the quadratic formula to solve for t:\r
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\n" ); document.write( "\n" ); document.write( "Starting with the general quadratic\r
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\n" ); document.write( "\n" ); document.write( "\"at%5E2%2Bbt%2Bc=0\"\r
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\n" ); document.write( "\n" ); document.write( "the general solution using the quadratic equation is:\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-b+%2B-+sqrt%28+b%5E2-4%2Aa%2Ac+%29%29%2F%282%2Aa%29\"\r
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\n" ); document.write( "\n" ); document.write( "So lets solve \"-5%2At%5E2%2B20%2At%2B20=0\" ( notice \"a=-5\", \"b=20\", and \"c=20\")\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-20+%2B-+sqrt%28+%2820%29%5E2-4%2A-5%2A20+%29%29%2F%282%2A-5%29\" Plug in a=-5, b=20, and c=20\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-20+%2B-+sqrt%28+400-4%2A-5%2A20+%29%29%2F%282%2A-5%29\" Square 20 to get 400 \r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-20+%2B-+sqrt%28+400%2B400+%29%29%2F%282%2A-5%29\" Multiply \"-4%2A20%2A-5\" to get \"400\"\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-20+%2B-+sqrt%28+800+%29%29%2F%282%2A-5%29\" Combine like terms in the radicand (everything under the square root)\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-20+%2B-+20%2Asqrt%282%29%29%2F%282%2A-5%29\" Simplify the square root (note: If you need help with simplifying the square root, check out this solver)\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-20+%2B-+20%2Asqrt%282%29%29%2F-10\" Multiply 2 and -5 to get -10\r
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\n" ); document.write( "\n" ); document.write( "So now the expression breaks down into two parts\r
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\n" ); document.write( "\n" ); document.write( "\"t+=+%28-20+%2B+20%2Asqrt%282%29%29%2F-10\" or \"t+=+%28-20+-+20%2Asqrt%282%29%29%2F-10\"\r
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\n" ); document.write( "\n" ); document.write( "Now break up the fraction\r
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\n" ); document.write( "\n" ); document.write( "\"t=-20%2F-10%2B20%2Asqrt%282%29%2F-10\" or \"t=-20%2F-10-20%2Asqrt%282%29%2F-10\"\r
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\n" ); document.write( "\n" ); document.write( "\"t=2-2%2Asqrt%282%29\" or \"t=2%2B2%2Asqrt%282%29\"\r
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\n" ); document.write( "\n" ); document.write( "So these expressions approximate to\r
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\n" ); document.write( "\n" ); document.write( "\"t=-0.82842712474619\" or \"t=4.82842712474619\"\r
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\n" ); document.write( "\n" ); document.write( "So our possible solutions are:\r
\n" ); document.write( "\n" ); document.write( "\"t=-0.82842712474619\" or \"t=4.82842712474619\"\r
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\n" ); document.write( "\n" ); document.write( "However, since a negative time doesn't make sense, our only solution is \"t=4.82842712474619\"\r
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\n" ); document.write( "\n" ); document.write( "So at about 4.8 seconds the ball will be 80 m high
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