document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=102223>Question 102223</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A coffee merchant combines coffee costing $5.20/lb with coffee costing $3.00/lb. How many pounds of each should be used to make 40 lbs. of a blend costing $4.00/lb?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74279 by </B><A HREF=/tutors/aboutme.mpl?userid=checkley75><B>checkley75(3666)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=checkley75><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74279\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 5.2X+3(40-X)=4*40<BR>\n" );
document.write( "5.2X+120-3X=160<BR>\n" );
document.write( "2.2X=160-120<BR>\n" );
document.write( "2.2X=40<BR>\n" );
document.write( "X=40/2.2<BR>\n" );
document.write( "X=18.18 POUND OF $5.20 COFFEE IS REQUIRED.<BR>\n" );
document.write( "40-18.18=21.82 POUNDS OF $3.00 COFFEE IS REQUIRED.<BR>\n" );
document.write( "PROOF<BR>\n" );
document.write( "5.2*18.18+3*21.82=160<BR>\n" );
document.write( "94.54+65.46=160<BR>\n" );
document.write( "160=160 </SPAN>\n" );
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