document.write( "Question 102225This question is from textbook
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document.write( ": you have $3.50 in dimes and quarters. If you have a total of 23 coins, how many of each type do you have? \n" );
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Algebra.Com's Answer #74278 by checkley75(3666)![]() ![]() ![]() You can put this solution on YOUR website! D+Q=23 OR D=23-Q \n" ); document.write( ".10D+.25Q=3.50 NOW REPLACE D WITH (23-Q) \n" ); document.write( ".10(23-Q)+.25Q=3.50 \n" ); document.write( "2.30-.1Q+.25Q=3.50 \n" ); document.write( ".15Q=3.50-2.30 \n" ); document.write( ".15Q=1.20 \n" ); document.write( "Q=1.20/.15 \n" ); document.write( "Q=8 NUMBER OF QUARTERS \n" ); document.write( "23-8=15 NUMBER OF DIMES. \n" ); document.write( "PROOF \n" ); document.write( ".10*15+.25*8=3.50 \n" ); document.write( "1.50+2.00=3.5 \n" ); document.write( "3.5=3.5 \n" ); document.write( " \n" ); document.write( " |