document.write( "Question 1126457: It is desired to have a 20-liter mixture of 60% alcohol. Two mixtures, one or 85% alcohol another of 35% of alcohol are to be used. How many liters of each will be required? \n" ); document.write( "
Algebra.Com's Answer #742777 by josgarithmetic(39628)\"\" \"About 
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Use variable for the higher available concentration material.\r
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\n" ); document.write( "\n" ); document.write( "x of 85%
\n" ); document.write( "20-x of 35%\r
\n" ); document.write( "\n" ); document.write( "Want 60% alcohol\r
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\n" ); document.write( "\n" ); document.write( "\"85x%2B35%2820-x%29=60%2A20\"\r
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