document.write( "Question 1126333: a grocery shopper bought 6 ib of steak and 20 ib of groundbeef the steak cost $5/ib more than the groundbeef and the total bill was $82 what was the price per pound for each type of meat?
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Algebra.Com's Answer #742642 by ikleyn(52788)![]() ![]() You can put this solution on YOUR website! . \n" ); document.write( " \r\n" ); document.write( "Let B be the price per pound of groundbeef, in dollars.\r\n" ); document.write( "\r\n" ); document.write( "Then the price per pound for steak is (B+5) dollars.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "6 lb of steak cost 6*(B+5) dollars.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "20 lb of groundbeef cost 20*B dollars.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "An equation for the total is\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 6*(B+5) + 20*B = 82 dollars.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Simplify and solve for B :\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 6B + 30 + 20B = 82\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " 26B = 82 - 30 = 52\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( " B = 52/26 = 2 dollars.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Answer. The price per pound of groundbeef is $2; the price per pound of steak is 2+5 = 7 dollars.\r\n" ); document.write( "\r\n" ); document.write( "\r\n" ); document.write( "Check. 6*7 + 20*2 = 82 dollars. ! Correct !\r\n" ); document.write( "\r \n" ); document.write( "\n" ); document.write( "Solved.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |