document.write( "Question 1126322: A broker has invested $21,000 in two mutual funds, one earning 9% annual interest and the other 14%. After 1 year, his combined interest is $2,790. How much was invested at each rate?? \n" ); document.write( "
Algebra.Com's Answer #742640 by addingup(3677)![]() ![]() You can put this solution on YOUR website! the total is 21,000 \n" ); document.write( "part of it at 9%, let it be x \n" ); document.write( "the rest at 14% will be 21,000-x \n" ); document.write( "--------------------------------------- \n" ); document.write( "0.09x + 0.14(21,000-x) = 2,790 \n" ); document.write( "0.09x + 2,940 - 0.14x \n" ); document.write( "-0.05x = -150 divide -150/-0.05 and remember -/- = + \n" ); document.write( "x = 3,000 \n" ); document.write( "The broker has $3,000 invested at 9% and 21,000-3000 = 18,000 at 14% \n" ); document.write( " |