document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1126331>Question 1126331</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi!\r<BR>\n" );
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document.write( "I have a linear equation question that says to solve for y. When I did the problem I got y=(ba-bx)/a but I'm not sure that is correct. the equation says:\r<BR>\n" );
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document.write( "(x/a)+(y/b)=1\r<BR>\n" );
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document.write( "Thank you,<BR>\n" );
document.write( "Maddie </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #742639 by </B><A HREF=/tutors/aboutme.mpl?userid=addingup><B>addingup(3677)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=addingup><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=addingup><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=742639\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x/a + y/b = 1 multiply both sides times a and b<BR>\n" );
document.write( "ab(x/a) + ab(y/b) = 1<BR>\n" );
document.write( "on the left a cancels a and on the right b cancels b, and you get:<BR>\n" );
document.write( "bx + ay = 1\r<BR>\n" );
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document.write( " </SPAN>\n" );
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