document.write( "Question 1126326: Caitlin drove from Greensville to Bluesburg at a speed of 50 mi/h. On the way back, she drove at 75 mi/h. The total trip took 7 1 h of driving time. Find the distance between these two cities. \n" ); document.write( "
Algebra.Com's Answer #742632 by josgarithmetic(39617)\"\" \"About 
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The total trip took 7 1 h of driving time. 

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\n" ); document.write( "\n" ); document.write( "71 hours seems like too long a time. There is a space between the two digits. Not sure if this really was intended as 7 hours or 71 hours. Decide which is it, and here just a variable will be used for that total drive time, T. You will decide which to use, from there.\r
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document.write( "                SPEEDS    TIMES     DISTANCE\r\n" );
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document.write( "G to B            50       d/50       d\r\n" );
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document.write( "B to G            75       d/75       d\r\n" );
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document.write( "TOTAL                       T\r\n" );
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\n" ); document.write( "\n" ); document.write( "\"d%2F50%2Bd%2F75=T\"\r
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\n" ); document.write( "\n" ); document.write( "\"150%28d%2F50%2Bd%2F75%29=150T\"\r
\n" ); document.write( "\n" ); document.write( "\"3d%2B2d=150T\"\r
\n" ); document.write( "\n" ); document.write( "\"5d=150T\"\r
\n" ); document.write( "\n" ); document.write( "\"d=30T\"
\n" ); document.write( "My guess is that supposed to be T=7 and then \"highlight_green%28d=210%29\".\r
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\n" ); document.write( "\n" ); document.write( "Otherwise, if T=71, then \"highlight_green%28d=2130%29\".
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