document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1126222>Question 1126222</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 	Fahrenheit 	Celcius <BR>\n" );
document.write( "Boiling point of water 	212° 	100° <BR>\n" );
document.write( "Freezing point of water 	32° 	0° <BR>\n" );
document.write( "Absolute zero 	–459.6° 	–273.1° <BR>\n" );
document.write( "1.	To convert from Fahrenheit to Celsius, subtract 32 and multiply by 59 .<BR>\n" );
document.write( "Write a formula to describe this relationship. Define any variables that you have used. <BR>\n" );
document.write( "2.	Mercury is liquid in the range from –38.20°F to 674.06°F. Use your formula to convert this range to degrees Celsius. <BR>\n" );
document.write( "3.	Rearrange the equation in a. to make Fahrenheit the subject of the formula. \r<BR>\n" );
document.write( "\n" );
document.write( "7. A ladder, of length 5 metres, is placed against a wall at an angle of 65° to the horizontal<BR>\n" );
document.write( "1.	Draw a diagram to represent the situation. <BR>\n" );
document.write( "2.	Use your knowledge of trigonometric ratios to calculate how high up the wall the ladder will reach. <BR>\n" );
document.write( "3.	How far will the foot of the ladder be from the base of the building? \r<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #742542 by </B><A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><B>josgarithmetic(39630)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=josgarithmetic><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=742542\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Too many separate questions in one posting.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(1) F and C temperatures\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "Identify two points and create the formula.<BR>\n" );
document.write( "Points (F,C) are (32,0) and (212,100).\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=C-0=%28%28100-0%29%2F%28212-32%29%29%28F-32%29 ALIGN=MIDDLE  ALT=\"C-0=%28%28100-0%29%2F%28212-32%29%29%28F-32%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > in point-slope form\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=C=%2810%2F18%29%28F-32%29 ALIGN=MIDDLE  ALT=\"C=%2810%2F18%29%28F-32%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=C=%285%2F9%29%28F-32%29 ALIGN=MIDDLE  ALT=\"C=%285%2F9%29%28F-32%29\"   DISABLED_style= \"max-width:90%; height:auto;\" >\r<BR>\n" );
document.write( "\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=C=%285%2F9%29F-160%2F9 ALIGN=MIDDLE  ALT=\"C=%285%2F9%29F-160%2F9\"   DISABLED_style= \"max-width:90%; height:auto;\" > slope-intercept form, which you might approximate as <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=C=%285%2F9%29F-17.8 ALIGN=MIDDLE  ALT=\"C=%285%2F9%29F-17.8\"   DISABLED_style= \"max-width:90%; height:auto;\" >.<BR>\n" );
document.write( "That is formula for Celsius as function of Fahrenheit.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "If you want F as a function of C, then just solve the equation for F.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "(2) and (3)<BR>\n" );
document.write( "You do those on your own. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );