document.write( "Question 1126088: Find the diameter of the largest circular pond that could fit in a triangular garden with verticies at (18,54),(-27,36),(27,-18, where a unit represents 1m
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Algebra.Com's Answer #742399 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "first use distance formula to find the length of the sides:
\n" ); document.write( " a triangular garden with vertices at \r
\n" ); document.write( "\n" ); document.write( "A=(\"18\",\"54\"), \r
\n" ); document.write( "\n" ); document.write( "B=(\"-27\",\"36\"),
\n" ); document.write( "C=(\"27\",\"-18\")\r
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\n" ); document.write( "\n" ); document.write( "find AB:\r
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Solved by pluggable solver: Distance Between 2 points
The distance formula is \"sqrt%28%28%28x%5B2%5D-x%5B1%5D%29%5E2%29%2B%28%28y%5B2%5D-y%5B1%5D%29%5E2%29%29\". Plug in the numbers,\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28%28%28-27-%2818%29%29%5E2%29%2B%28%2836-%2854%29%29%5E2%29%29\" \r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28-45%5E2%2B-18%5E2%29\" The distance is 48.4664832642105.\r
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\n" ); document.write( "\n" ); document.write( "AB=c ->\"c=48.5\"\r
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\n" ); document.write( "\n" ); document.write( "find BC:\r
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Solved by pluggable solver: Distance Between 2 points
The distance formula is \"sqrt%28%28%28x%5B2%5D-x%5B1%5D%29%5E2%29%2B%28%28y%5B2%5D-y%5B1%5D%29%5E2%29%29\". Plug in the numbers,\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28%28%28-27-%2827%29%29%5E2%29%2B%28%2836-%28-18%29%29%5E2%29%29\" \r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28-54%5E2%2B54%5E2%29\" The distance is 76.3675323681471.\r
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\n" ); document.write( "\n" ); document.write( "BC=a ->\"a=76.4\"\r
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\n" ); document.write( "\n" ); document.write( "find AC:
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Solved by pluggable solver: Distance Between 2 points
The distance formula is \"sqrt%28%28%28x%5B2%5D-x%5B1%5D%29%5E2%29%2B%28%28y%5B2%5D-y%5B1%5D%29%5E2%29%29\". Plug in the numbers,\r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28%28%2818-%2827%29%29%5E2%29%2B%28%2854-%28-18%29%29%5E2%29%29\" \r
\n" ); document.write( "\n" ); document.write( "\"sqrt%28-9%5E2%2B72%5E2%29\" The distance is 72.5603197346869.\r
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\n" ); document.write( "\n" ); document.write( "AC=b ->\"b=72.6\"\r
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\n" ); document.write( "\n" ); document.write( "Here is a formula in terms of the three sides:\r
\n" ); document.write( "\n" ); document.write( " If the sides have length \"a\",\"b\", \"c\", we define the semi-perimeter s to be half their sum, so \"s+=+%28a%2Bb%2Bc%29%2F2\". \r
\n" ); document.write( "\n" ); document.write( "\"s+=+%2876.4%2B72.6%2B48.5%29%2F2\"
\n" ); document.write( "\"s+=+98.75\"\r
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\n" ); document.write( "\n" ); document.write( "Given this, the radius is given using the following:\r
\n" ); document.write( "\n" ); document.write( " \"+r%5E2+=+%28s+-+a%29%2A%28s+-+b%29%2A%28s+-+c%29+%2F+s\"\r
\n" ); document.write( "\n" ); document.write( " \"+r%5E2+=+%2898.75+-+76.4%29%2A%2898.75+-+72.6%29%2A%2898.75+-+48.5%29+%2F+98.75\"\r
\n" ); document.write( "\n" ); document.write( " \"+r%5E2+=+297.4\"\r
\n" ); document.write( "\n" ); document.write( "Take the square root of this expression to find \"r\".\r
\n" ); document.write( "\n" ); document.write( " \"+r+=+sqrt%28297.4%29\"\r
\n" ); document.write( "\n" ); document.write( "\"+r+=+17.25\" meters\r
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\n" ); document.write( "\n" ); document.write( "then, the diameter is \"d=34.5\" meters\r
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