document.write( "Question 1126069: Simplify {[3^(2n)] - 1} / {[3^(n+1)] - 3}. Thank you :) \n" ); document.write( "
Algebra.Com's Answer #742387 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "Simplify: \"%28%283%5E%282n%29%29+-+1%29+%2F+%28%283%5E%28n%2B1%29%29+-+3%29\"

\n" ); document.write( "The numerator factors as the difference of squares:

\n" ); document.write( "\"3%5E%282n%29-1+=+%283%5En-1%29%283%5En%2B1%29\"

\n" ); document.write( "In the denominator, take one factor of 3 out of \"3^(n+1)\"; then factor out the common factor of the two terms:

\n" ); document.write( "\"3%5E%28n%2B1%29-3+=+3%283%5En%29-3+=+3%283%5En-1%29\"

\n" ); document.write( "Now simplify:

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