document.write( "Question 1126064: Please help. FREE FALL. A girl throws a ball vertically upward with a speed of 20 ft/s from the roof of a building 60 ft high. How long will it take the ball to reach the ground? What will be its speed when it strikes the ground?
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Algebra.Com's Answer #742381 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! a) To find the time it takes to reach the ground, we solve this equation \n" ); document.write( ": \n" ); document.write( "s(t) = -16t^2 +v(0)t +h, when s(t)=0, v(0)=20, h=60 \n" ); document.write( ": \n" ); document.write( "-16t^2 +20t +60 = 0 \n" ); document.write( ": \n" ); document.write( "divide both sides of = by -4 \n" ); document.write( ": \n" ); document.write( "4t^2 -5t -15 = 0 \n" ); document.write( "use the quadratic formula to solve \n" ); document.write( ": \n" ); document.write( "t = (-(-5) +square root((-5)^2 -4*(4)(-15)))/(2*4) = 2.6599 \n" ); document.write( ": \n" ); document.write( "t = (-(-5) -square root((-5)^2 -4*(4)(-15)))/(2*4) = -1.4099 \n" ); document.write( ": \n" ); document.write( "**************************************************** \n" ); document.write( "it takes the ball 2.6599 seconds to reach the ground \n" ); document.write( "**************************************************** \n" ); document.write( ": \n" ); document.write( "b) Due to symmetry, the ball will be moving 20 ft/sec when it comes back down to the point from which you threw it on the building. So you can reduce the problem to describing a ball thrown off a building with initial velocity 20 ft/sec downward. \n" ); document.write( ": \n" ); document.write( "The balls position respect to time is then, \n" ); document.write( ": \n" ); document.write( "s(t) = 60 -20t -16t^2 \n" ); document.write( ": \n" ); document.write( "to find t when s = 0, solve \n" ); document.write( ": \n" ); document.write( "-16t^2 -20t +60 = 0 \n" ); document.write( ": \n" ); document.write( "divide both sides of = by -4 \n" ); document.write( ": \n" ); document.write( "4t^2 +5t -15 = 0 \n" ); document.write( ": \n" ); document.write( "use quadratic formula to solve for t \n" ); document.write( ": \n" ); document.write( "t = (-5 +square root(5^2 -4*(4)(-15)))/(2*4) = 1.4099 \n" ); document.write( ": \n" ); document.write( "t = (-5 -square root(5^2 -4*(4)(-15)))/(2*4) = -2.6599 \n" ); document.write( ": \n" ); document.write( "we reject the negative time value \n" ); document.write( ": \n" ); document.write( "t = 1.4099 seconds \n" ); document.write( ": \n" ); document.write( "since acceleration is constant for this problem, we have \n" ); document.write( ": \n" ); document.write( "v(t) = -20 -32t \n" ); document.write( ": \n" ); document.write( "v(0.7352) = -20 -32(1.4099) = −65.1168 \n" ); document.write( ": \n" ); document.write( "The negative sign comes from calling the upwards direction + and the downwards direction − \n" ); document.write( ": \n" ); document.write( "************************************************************* \n" ); document.write( "The ball's velocity is 65.1168 ft/sec when it hits the ground \n" ); document.write( "************************************************************* \n" ); document.write( ":\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |