document.write( "Question 1126056: Sound intensity varies inversely as the square of the distance from the sound source. If you are in a movie theater and you change your seat to one that is six times as far from the​ speakers, how does the new sound intensity compare with that of your original​ seat?\r
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Algebra.Com's Answer #742375 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
\"+I%5B1%5D+=+k%2A%28+1%2Fd%5E2+%29+\"
\n" ); document.write( "\"+I%5B2%5D+=+k%2A%28+1%2F%286d%29%5E2%29+\"
\n" ); document.write( "\"+I%5B2%5D%2FI%5B1%5D+=+k%2A%28+1%2F%286d%29%5E2+%29+%2F%28+k%2A%28+1%2Fd%5E2+%29%29+\"
\n" ); document.write( "\"+I%5B2%5D%2FI%5B1%5D+=+d%5E2+%2F+%286d%29%5E2+\"
\n" ); document.write( "\"+I%5B2%5D%2FI%5B1%5D+=+1%2F36+\"
\n" ); document.write( "the sound intensity is 1/36th of what it was\r
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