document.write( "Question 1126053: Hi!\r
\n" ); document.write( "\n" ); document.write( "I'm a little confused on this algebra word problem:\r
\n" ); document.write( "\n" ); document.write( "One fifth of a man's age 6 years ago equals one seventh of his age 10 years hence. How old is he now?\r
\n" ); document.write( "\n" ); document.write( "Is the equation 1/5x-6=1/7x+10 if X equals the man's age? If that is not the equation, could you explain how to get the equation and also how to solve the equation? \r
\n" ); document.write( "\n" ); document.write( "Thank you so much!
\n" ); document.write( "-Maddie \n" ); document.write( "
Algebra.Com's Answer #742358 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
One fifth of a man's age 6 years ago equals one seventh of his age 10 years hence. How old is he now?
\n" ); document.write( ":
\n" ); document.write( "this is the equation, just remember the brackets
\n" ); document.write( "\"1%2F5\"(x-6) = \"1%2F7\"(x+10)
\n" ); document.write( "Get rid of the denominators, multiply both sides by 35
\n" ); document.write( "7(x-6) = 5(x+10)
\n" ); document.write( "distribute
\n" ); document.write( "7x - 42 = 5x + 50
\n" ); document.write( "7x - 5x = 50 + 42
\n" ); document.write( "2x = 92
\n" ); document.write( "x = 92/2
\n" ); document.write( "x = 46 yr old now
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\n" ); document.write( "check
\n" ); document.write( "\"1%2F5\"(46-6) = \"1%2F7\"(46+10)
\n" ); document.write( "\"1%2F5\"(40) = \"1%2F7\"(56)
\n" ); document.write( "8 = 8\r
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