Algebra.Com's Answer #742350 by ikleyn(52781)  You can put this solution on YOUR website! .\r \n" );
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document.write( " It is very good problem for someone who wants to check how creative is his (or her) mind in solving problems \n" );
document.write( " in Math and Physics.\r \n" );
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document.write( "There are two basic stable configurations for the spherical balls in this cylinder.\r\n" );
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document.write( "One configuration is shown in the Figure on the right.\r\n" );
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document.write( "The larger ball lies at the bottom of the cylinder and touches the cylinder's vertical lateral surface. \r\n" );
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document.write( "The smaller ball is above the bottom. It touches the larger ball and also touches vertical lateral \r\n" );
document.write( "surface of the cylinder.\r\n" );
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document.write( "The Figure shows a vertical section of the cylinder and the two balls by that existing and unique \r\n" );
document.write( "vertical plane which contains the cylinder's vertical axis and the centers of the two balls.\r\n" );
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document.write( "In the Figure, you see a right angled triangle shown in red.\r\n" );
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document.write( "The hypotenuse of this triangle is the segment AB connecting the centers of balls.\r\n" );
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document.write( "This segment goes through the tangent point, and its length is 7 + 3 = 10 cm.\r\n" );
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document.write( "You can easily find the horizontal leg of this triangle, x.\r\n" );
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document.write( "From the equation 7 + x + 3 = 18 you have x = 18 - 7 - 3 = 8.\r\n" );
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document.write( "Then the vertical leg of this triangle is = = 6 cm.\r\n" );
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document.write( "Thus the height of the highest point of the small ball over the cylinder bottom is 7 + 6 + 3 = 16 centimeters.\r\n" );
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document.write( "It defines the minimal required upper level of 16 cm of the water in the cylinder after submerging the balls.\r\n" );
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document.write( "With it, the volume equation is\r\n" );
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document.write( " = W + + , or\r\n" );
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document.write( "W = - = = = \r\n" );
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document.write( "where W is the minimal required volume of the water before submerging the balls.\r\n" );
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document.write( "Now, how much of water has to be poured out so that there is just enough water to cover both balls? - It is the difference \r\n" );
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document.write( " cm^3 MINUS cm^3 = cm^3 = cm^3. ANSWER\r\n" );
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document.write( "The other stable configuration is when the small ball lies on the bottom, while the larger ball leans on it.\r \n" );
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document.write( "The analysis is very similar in this case.\r \n" );
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document.write( " * * * Solved * * * \r \n" );
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