document.write( "Question 1125996: A rock is thrown upward from a bridge into a river below. The function f(t)=-16t^2+38t+90 determines the height of the rock above the surface of the water (in feet) in terms of the number of seconds t since the rock was thrown. \r
\n" ); document.write( "\n" ); document.write( "a. What is the bridge's height above the water?\r
\n" ); document.write( "\n" ); document.write( "b. How many seconds after being thrown does the rock hit the water?\r
\n" ); document.write( "\n" ); document.write( "c. How many seconds after being thrown does the rock reach its maximum height above the water?\r
\n" ); document.write( "\n" ); document.write( "d. What is the rock's maximum height above the water?
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Algebra.Com's Answer #742329 by Boreal(15235)\"\" \"About 
You can put this solution on YOUR website!
The height is 90 feet, the constant in the equation
\n" ); document.write( "maximum height is where t=-b/2a of the quadratic or -38/-32 or t=19/16 sec
\n" ); document.write( "putting that into the equation, height max is 112.6 feet\r
\n" ); document.write( "\n" ); document.write( "set it equal to 0 to find the landing time
\n" ); document.write( "16t^2-38t-90=0, rewriting with positive first term
\n" ); document.write( "t=(1/32)(38+/- sqrt (1444+5760)0; sqrt 7200=84.85
\n" ); document.write( "t=3.84 sec until it hits the water\r
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