document.write( "Question 1125900: Boxes of a certain cereal say they hold 15 oz. To make sure they​ do, the manufacturer fills the box to a mean weight of 15.3 ​oz, with a standard deviation of 0.15 oz. If the weights have a normal​ curve, what percentage of boxes actually contain 15 oz or​ more? \n" ); document.write( "
Algebra.Com's Answer #742243 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
mean is 15.3
\n" ); document.write( "standard deviation is .15
\n" ); document.write( "you want to know what percentage of boxes actually contain 15 ounces or more.
\n" ); document.write( "the following graph shows that it will be 97.72%.
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\n" ); document.write( "\n" ); document.write( "if you want to find the z-score, you would do the following.\r
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\n" ); document.write( "\n" ); document.write( "z = (x-m)/s
\n" ); document.write( "z is the z-score
\n" ); document.write( "m is the mean
\n" ); document.write( "x is the raw score
\n" ); document.write( "s is the standard deviation.\r
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\n" ); document.write( "\n" ); document.write( "formula becomes z = (15 - 15.3) / .15 = -2
\n" ); document.write( "look up in the z-score table for the area to the left of a z-score of -2 to find that the area to the left of the z-score is .0228.
\n" ); document.write( "the area to the right of that z-score is therefore 1 - .0228 = .9772\r
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\n" ); document.write( "\n" ); document.write( "the z-score calculator i used will show you that as well, as shown below.
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\n" ); document.write( "\n" ); document.write( "the z-score table i used can be found at http://www.z-table.com/\r
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\n" ); document.write( "\n" ); document.write( "it appears i'm having trouble uploading the graphs.
\n" ); document.write( "rest assured that the probability is 97.72%.\r
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\n" ); document.write( "\n" ); document.write( "i'll have to do some troubleshooting and will update the solution when i'm successful.\r
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\n" ); document.write( "\n" ); document.write( "in the meantime, look up the table and you'll find that the area to the left of a z-score of -2 is .0228 which means that the area to the right of that z-score score is .9772.\r
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